How much heat must be absorbed by 525 grams of water to raise its temperature by 45- C -A- 8-87 - 104 JB- 8-97 - 104 JC- 6-87 - 104 JD- 9-87 - 104 J

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Question

How much heat must be absorbed by 525 grams of water to raise its temperature by 45° C?

6.87 x $10^{4}$ J

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8.87 x $10^{4}$ J

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8.97 x $10^{4}$ J

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9.87 x $10^{4}$ J

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Solution

The correct option is D
9.87 x $10^{4}$ J

mw = 525 g

cw = 4.18 J/g·K

∆T = 45° C

Q = mwcw∆Tw

Q = 525 x 4.18 x 45 = 9.87 x $10^{4}$ J (Answer)

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How much heat must be absorbed by 525 grams of water to raise its temperature by 45° C?

The correct option is D 9.87 x 104 J mw = 525 g cw = 4.18 J/g·K ∆T = 45° C Q = mw*cw*∆Tw Q = 525 x 4.18 x 45 = 9.87 x 104 J (Answer)

The correct option is D
9.87 x $10^{4}$ J

mw = 525 g

cw = 4.18 J/g·K

∆T = 45° C

Q = mwcw∆Tw

Q = 525 x 4.18 x 45 = 9.87 x $10^{4}$ J (Answer)