How much ice must be added to 100 g of water at 30-C in order to reduce its temperature to 20-C-

In a laboratory experiment for finding specific latent heat of ice, 100 g of water at 30^oC was taken in a calorimeter made of copper and of mass 10 g. When 10 g of ice at 0^oC was added to the mixture and kept within the liquid till the ice melted completely, the final temperature of the mixture was found to be 20^oC.

Calculate the value of the latent heat of fusion of ice from the data discussed above.

Q. How much heat is required to raise the temperature of

100 g

of water from

5^{\circ} C

95^{\circ} C

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How much ice must be added to 100g of water at 30∘C in order to reduce its temperature to 20∘C?

The correct option is A 10gLet the required mass of ice be m.m×80+m×1×(20−0)=100×1×(30−20)⇒80m+20m=1000⇒m=1000100=10g

How much ice must be added to $100 g$ of water at $30^{\circ} C$ in order to reduce its temperature to $20^{\circ} C$ ?

The correct option is A $10 g$
Let the required mass of ice be $m$ .
$m \times 80 + m \times 1 \times (20 - 0) = 100 \times 1 \times (30 - 20) \Rightarrow 80 m + 20 m = 1000 \Rightarrow m = \frac{1000}{100} = 10 g$