Given
2x^2-x+3 >x^2-x
that is
x^2>-3
may be this is your final answer
(-x from both sides is canceled
and x^2 is bring to one side and constant term to another side)
x>root(-3)
can be written in complex form
that is root(-1)=i
so root(-3)=i root(3)
so x>i root(3)