Question

How much mass of $H_{2}S{O}_4$ will be required for preparing its $200$ml aqueous solution of $0.5$ molarity concentration?

Answer 1

Molarity=$\frac{n\left(moles\right)}{Volume\left(L\right)}$

$0.5=\frac{\frac{m}{M_w}}{\frac{200}{1000}L}$

$0.5=\frac{m\times 1000}{98\times 200}$

$m=\frac{0.5\times 98\times 200}{1000}$

$m=19.6grams$