How much mass of water at 100 ℃ must be heated so as to form steam at 100 ℃ when a burner supplies 45200 J of heat energy? Specific latent heat of vapourisation of water is 2260 J /g

10 g

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20 g

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30 g

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40 g

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Solution

The correct option is B
20 g

Given Q = 45200 J

L = 2260 J/g

Q = mL

M = Q/L

M=45200/2260

M = 20g

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Calculate the heat energy required to convert completely $10 k g$ of water at $50 ° C$ into steam at $100 ° C$ , given that the specific heat capacity of water is $4200 J / (k g ° C)$ and the specific latent heat of vaporisation of water is $2260 k J / k g$ .