How much metal sheet is required to make an open cylindrical tank of radius $4.2 m$ and height $15 m$ ?

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Solution

Mutel sheet = CSA of cylindrical + Base of cylindrical
$= 2 π r h + π r^{2}$
$= \frac{2 \times 22}{7} \times 4.2 \times 15 + \frac{22}{7} \times 4.2 \times \times 4.2$
$= 451.44 m^{2}$

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How much metal sheet is required to make an open cylindrical tank of radius 4.2 m and height 15 m?

Mutel sheet = CSA of cylindrical + Base of cylindrical =2πrh+πr2=2×227×4.2×15+227×4.2××4.2=451.44m2

How much metal sheet is required to make an open cylindrical tank of radius $4.2 m$ and height $15 m$ ?

Mutel sheet = CSA of cylindrical + Base of cylindrical
$= 2 π r h + π r^{2}$
$= \frac{2 \times 22}{7} \times 4.2 \times 15 + \frac{22}{7} \times 4.2 \times \times 4.2$
$= 451.44 m^{2}$