How much milk should be added to 800 dl of a 15% milk solution to make the strength 32%?
How much milk should be added to 800 dl of a 15% milk solution to make the strength 32%?
The correct option is C 200
Let x dl of pure milk be added. The concentration of pure milk is 100%
Total milk content in x dl of milk = x * 100% = x dl
Total milk content in 800 dl of 15% mixture = 800 * 15% = 120 dl
Therefore, total milk content in final mixture = x + 120
Total volume of mixture = 800 + x
Hence concentration of milk in final mixture = x+120800+x
This is given to be 32%.
Hence x+120800+x = 32 %
Solving, we get x = 200 dl.
Shortcut- Using Alligation
There may be different ways to solve this question, but one of the fastest approaches is using the concept of Alligation. Pure milk has 100% concentration, and it is mixed with a solution with 15% milk to make it 32%. This information can be used to get the ratio of the mixture as follows
For every 4 parts of 15% milk, 1 parts of 100% milk needs to be added.
Hence to 800 dl of the 15% solution, 8004 = 200 dl of 100% milk needs to be added
200
Let x dl of pure milk be added. The concentration of pure milk is 100%
Total milk content in x dl of milk = x * 100% = x dl
Total milk content in 800 dl of 15% mixture = 800 * 15% = 120 dl
Therefore, total milk content in final mixture = x + 120
Total volume of mixture = 800 + x
Hence concentration of milk in final mixture = x+120800+x
This is given to be 32%.
Hence x+120800+x = 32 %
Solving, we get x = 200 dl.
Shortcut- Using Alligation
There may be different ways to solve this question, but one of the fastest approaches is using the concept of Alligation. Pure milk has 100% concentration, and it is mixed with a solution with 15% milk to make it 32%. This information can be used to get the ratio of the mixture as follows
For every 4 parts of 15% milk, 1 parts of 100% milk needs to be added.
Hence to 800 dl of the 15% solution, 8004 = 200 dl of 100% milk needs to be added
