Question 18
How much momentum will a dumbbell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be $10 m s^{- 2}$ .

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Solution

Mass of the dumbbell, m = 10 kg
Distance covered by the dumbbell, s = 80 cm = 0.8 m
Acceleration in the downward direction, a = 10 $m s^{- 2}$
Initial velocity of the dumbbell, u = 0
Final velocity of the dumbbell (when it was about to hit the floor) = v
According to the third equation of motion:
$v^{2} = u^{2} + 2 a s$
$v^{2} = 0 + 2 (10) 0.8$
$\Rightarrow$ v = 4 $m s^{- 1}$
Hence, the momentum with which the dumbbell hits the floor is = mv = 10 $\times$ 4 = 40 kg $m s^{- 1}$

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Conservation of Momentum

Standard IX Physics

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Question 18 How much momentum will a dumbbell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 ms−2.

Question 18
How much momentum will a dumbbell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be $10 m s^{- 2}$ .