How much momentum will an object of mass $10 k g$ transfer to the floor if its falls from a height of $5 m$ (a=g=10m $s^{- 2}$ )

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Solution

Velocity when reached to ground
$v = \sqrt{2 g h} = \sqrt{2 \times 10 \times 5}$
$= \sqrt{100}$
$v = 10 m / s e c$
initial momentum before collision $p i = m v = 10 \times 10 = 100 k g m sec$
final momentum $P_{o} = 0$
momentum transferred = $P i - P_{0}$
$= 100 - 0$
$100 k h m / s e c$

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How much momentum will an object of mass 10kg transfer to the floor if its falls from a height of 5m(a=g=10ms−2)

Velocity when reached to groundv=√2gh=√2×10×5=√100v=10m/secinitial momentum before collision pi=mv=10×10=100kgmsecfinal momentum Po=0momentum transferred =Pi−P0=100−0100khm/sec

How much momentum will an object of mass $10 k g$ transfer to the floor if its falls from a height of $5 m$ (a=g=10m $s^{- 2}$ )

Velocity when reached to ground
$v = \sqrt{2 g h} = \sqrt{2 \times 10 \times 5}$
$= \sqrt{100}$
$v = 10 m / s e c$
initial momentum before collision $p i = m v = 10 \times 10 = 100 k g m sec$
final momentum $P_{o} = 0$
momentum transferred = $P i - P_{0}$
$= 100 - 0$
$100 k h m / s e c$