Question

Question 95

How much more percent seats were won by X as compared to Y in assembly election in the state based on the data given below?

$\begin{array}{c}\\ \text{Party}\text{Won(out of 294)}\\ X158\\ Y105\\ Z18\\ W13\end{array}$

Answer 1

On the basis of above give table
The total number of seats won by party X = 158
The total number of seats won by party Y = 105
$\therefore$ Total number of seats in election = 294
$\therefore$ Percentage of seats won by party $X=\frac{158}{294}\times 100=53.74\%$
$\therefore$ Percentage of seats won by party $Y=\frac{105}{294}\times 100=35.71\%$
So, difference of percentage = (53.74 - 35.71) % = 18.03 %
Hence, party X won 18.03 % compared to party Y.