How much must be a 0.02M solution of sodium acetate be diluted at 25∘C in order to double the degree of hydrolysis?
4 times
Let 'h' be the initial degree of hydrolysis
Kh=Ch2=0.2h2→(i)
The concentration becomes C1 when degree of hydrolysis is 2h,K′h=C1(2h)2=4C1h2→(ii)
Dividing Eqs (i) by (ii)
KhK′h=0.2h24C1 h2 ; 1=0.24C1
C1=0.24=0.05M
Now, from M1V1=M2V2
0.2V1=0.05V2
⇒V2=0.20.05V1=4V1
Therefore, the solution a must be diluted four times