How much oxygen is required for complete combustion of $560 g$ of ethene?

6.4 k g

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1.92 k g

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2.8 k g

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9.6 k g

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Solution

The correct option is B $1.92 k g$
Balanced reactio is:
$C_{2} H_{4} + 3 O_{2} \to 2 C O_{2} + 2 H_{2} O$
molar mass of $C_{2} H_{4}$ =28 g
molar mass of $O_{2}$ =32 g
from the reaction $3 \times 32 = 96 g O_{2}$ is required for 28 g ethene.
thus 560 g ethene will require $= \frac{96}{28} \times 560 = 1920 g O_{2}$
or 1.92 kg oxygen
option B is correct

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