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Question

How much quantity of electricity has to be passed through 200 ml of 0.5M CuSO4 solution to completely deposit copper?

A
9.65×104C
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B
1.93×104
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C
3.86×105C
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D
2.895×105C
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Solution

The correct option is B 1.93×104
Moles of CuSO4=200×0.51000=0.1Mole
Charge required to convert 0.1M Cu2+ to Cu=2×96500×0.1=1.93×104

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