How much quantity of silver is deposited when the current of one ampere passes per second through the circuit?

1.123 \times 10^{- 6} k g

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1.123 k g

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1.123 \times 10^{- 4} k g

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1.123 \times 10^{- 3} k g

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Solution

The correct option is A $1.123 \times 10^{- 6} k g$

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