How much quicklime can be obtained from $25$ grams of $C a C O_{3}$ ?

18

No worries! We‘ve got your back. Try BYJU‘S free classes today!

56

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

28

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $14$ g
The reaction is $C a C O_{3} ⇌ C a O + C O_{2}$ .

One mole of calcium carbonate on decomposition gives one mole of calcium oxide.

The molecular weight of calcium carbonate and calcium oxide are $100$ g/mol and $56$ g/mol respectively.

The decomposition of $100$ g of calcium carbonate will give $56$ g of calcium oxide.

Hence, the decomposition of $25$ g of calcium carbonate will give $14$ g of calcium oxide (quicklime).

Suggest Corrections

Similar questions

50 g

C a C O_{3} (s)

C a C O_{3}

56

C a C O_{3}

50 g

C a C O_{3} (s)

Calculate the gram molecular mass of $N_{2}$ , if $360 c m^{3}$ at STP weighs 0.45 g.

Join BYJU'S Learning Program