You visited us 2 times! Enjoying our articles? Unlock Full Access!

Electrolytes

How much shou...

Question

How much should sodium acetate be added to 0.1 M solution of $C H_{3} C O O H$ to give a solution of $p H = 5.5$ ( $p K_{a}$ of $C H_{3} C O O H = 4.5$ )?

0.1 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.2 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.0 M

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10.0 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $1.0 M$
The expression for the pH of the acidic buffer solution is as given below.
$p H = p K_{a} + l o g \frac{[s a l t]}{[a c i d]}$ .
$p K_{a} = 4.5$ .
Substitute values in the above equation.
$5.5 = 4.5 + l o g \frac{[s a l t]}{0.1}$
Hence, $[s a l t] = 1.0 M$ .

Suggest Corrections

Similar questions

50 m l 0.1 M N a O H

50 m l

0.1 M

C H_{3} C O O H

p H

{C H}_{3} C O O H = 4.7447

log 20 = 1.3

p H

50

0.1

25

0.2

C H_{3} C O O H

p K_{a}

C H_{3} C O O H

4.8

p H = 5.74

C H_{3} C O O H

C H_{3} C O O N a

0.01 M

C H_{3} C O O H

K_{a} (C H_{3} C O O H) = 1.8 \times 10^{- 5}

l o g (1.8) = 0.26

C H_{3} C O O H

20 m L

0.2 M

50 m L

0.2 M

70 m L

p H

C H_{3} C O O H

1.8 \times 10^{- 5}

Join BYJU'S Learning Program