Question

How much steam at ${100}^o$C will just melt $2700$g of ice at $-{10}^o$C. (Sp. heat of ice $=0.5$ and latent heat of steam $=540$ cal $g^{-1}$)

Answer 1

Let the required mass of steam be $m$

Now,

$m\times 540=2700\times 0.5\times [0-(-10\left)\right]+2700\times 80\Rightarrow 540\times m=13500+216000\Rightarrow m=\frac{229500}{540}=425g$