Question

How much thermal energy should be added to $3.45gNe$ in a $10$ liter flask to raise the tempereture from $0^{o}C$ to ${100}^{o}C$. (Atomic weight $Ne=20.18$)?

Answer 1

By using the formula ${nC}_{Process}\left(dt\right)$ which is equal to heat, and here heat is converted into thermal energy.

Here process is isochoric.

So, $C_{Process}changesto{C}_{isochoric}$

$=\frac{3}{2R}$

$n{C}_{isochoric}\left(dt\right)=\left(\frac{3.45}{20.18}\right)\times (\frac{3}{2}\times 2)\times (100-0)$

$=5.146cal$