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1st Equation of Motion

How much time...

Question

How much time does it take to go from the ground to its highest point?

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Solution

$f r o m t h e w i n d o w t h e f o o t b a l l g o e s u p t o a h e i g h t o f \frac{u^{2}}{2 g} = \frac{5^{2}}{20} = 1.25 m h e i g h t a b o v e t h e g r o u n d = 15 + 1.25 = 16.25 m t i m e t a k e n t o r e a c h t h e m a x i m u m h e i g h t = t i m e t a k e n i n r e a c h i n g g r o u n d f r o m t h e m a x h e i g h t h = \frac{1}{2} {g t}^{2} \Rightarrow t = \sqrt{\frac{2 h}{g}} = \sqrt{\frac{32.5}{10}} = 1.802 s$

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