How much volume of 18M & 4M sulphuric acid must be mixed to get 1litre of an 8M solution of sulphuric acid?

Open in App

Solution

Let us take = x litres of 18 M sulphuric and y litres of 4M solution.
Now, finally we need 1 litre of 8M solution
So, x litre + y litre = L litre
Or x + y = 1 - (i)
and, $18 M \times x l i t r e + 4 M \times y l i t r e s = 8 M \times 1 l i i t r e$
$\Rightarrow 18 x + 4 y = 8$ -(ii)
Solve (i) & (ii)
from (i), $x + y = 1 \Rightarrow 4 x + 4 y = 4$ (iii)
(ii) - (iii) 18x + 4y = 8
$\frac{4 x + 4 y = 4}{14 x = 4}$
$x = \frac{4}{14} = \frac{2}{7}$
$x + y = 1 \Rightarrow y = 1 - \frac{2}{7} = \frac{5}{7}$
So, take 47 litre of 18 M & $\frac{5}{7}$ litre of 4M solution

Suggest Corrections

Similar questions

Q. What volume of

98

% sulphuric acid (in ml) should be mixed with water to obtain

200 m L

15

% solution of sulphuric acid by weight? Given density of

H_{2} O = 1.00 g c m^{- 3}

, sulphuric acid

(98

= 1.88 g c m^{- 3}

and sulphuric acid

(15

= 1.12 g c m^{- 3}

Q. Jackie has two solutions that are

2

percent sulphuric acid and

12

percent sulphuric acid by volume respectively. If these solutions are mixed in appropriate quantities to produce

60

litres of a solution that is

5

percent sulphuric acid, approximately how many litres of the

2

percent solution will be required?

What volume of 95% sulphuric acid (density=1.85g/cm3)and what mass of water must be taken to prepare 100cm3 of 15%solution of sulphuric acid (density=1.10g/cm3)?

Q. A container contains 10 litres mixture in which there is 10% sulphuric acid. How much sulphuric acid is to be added to make the solution to contain 25% sulphuric acid?

Q. Calculate the volume of concentrated sulphuric acid (molarity = 18 M) required to prepare 250 mL of 2 M acid solution.

Join BYJU'S Learning Program