How much volume of air will be needed for complete combustion of 10 lit. of ethane?
A
135 lit.
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B
35 lit.
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C
175 lit.
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D
205 lit.
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Solution
The correct option is B 175 lit. Balance equation: 2C2H6+7O2→4CO2+6H2O According to reaction 7 mole of oxygen required for 2 mole of ethane so for 10 lit of ethane 35 lit of oxygen is required. As air contains only 20% oxygen so volume of air required is 35×5=175 lit.