Question

How much volume of $C{O}_2$ at $S.T.P$ is liberated by the combustion of $100c{m}^3$ of propane $\left(C_3{H}_8\right)$?

• A. $100$ $c{m}^3$
• B. $200$ $c{m}^3$
• C. $300$ $c{m}^3$
• D. $400$ $c{m}^3$

Answer 1

The correct option is C $300$ $c{m}^3$

The balanced chemical reaction is $C_3{H}_8+5O_2\to 3C{O}_2+4H_{2}O$.

$1$ mol ($22.4$ L at STP) of propane produces $3$ mol ($3\times 22.4$ L at STP) of $C{O}_2$.

Thus, $100$ $c{m}^3$ of propaneat STP will produce $\frac{100c{m}^3}{22.4}\times 3\times 22.4L=300c{m}^3$ at STP of $C{O}_2$.