How much water, in liters, must be added to 0.5 L of 6 M HCl to make it 2 M?

0.33

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0.5

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1.5

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Solution

The correct option is A 1
Molarity = $\frac{M a s s o f t h e s o l u t e}{(M o l a r m a s s o f t h e s o l u t e) \times (V o l . o f s o l n . i n l i t e r s)}$

Mass of solute will remain same before and after mixing water.
so
$M_{1} V_{1}$ $=$ $M_{2} V_{2}$
or
$V_{2}$ $=$ $6 \times 0.5 / 2$ $=$ $1.5 L$
this is final total volume so water added $=$ $1.5 - 0.5$ $=$ $1 L$

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