How much water, in litres, must be added to $0.5 L$ of $6 M$ $H C l$ to make it $2 M$ ?

0.33

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0.5

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1

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1.5

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2

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Solution

The correct option is C $1$
Let V liters, must be added to 0.5L of 6M HCl to make it 2M.
The mass of the solute HCl remain the same, thus
$M_{1} V_{1} = M_{2} V_{2}$
$6 M \times 0.5 L = 2 M \times (0.5 + V) L$
$(0.5 + V) L = 1.5 L$
$V = 1 L$

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