How much water is to be added to dilute 10mL of 10N HCI to make it decinormal?

990mL

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1010mL

No worries! We‘ve got your back. Try BYJU‘S free classes today!

100mL

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1000mL

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 990mL
$N_{1} V_{1}$ = $N_{2} V_{2}$
$10 \times 10$ = $N_{2} \times 0.1$
$N_{2}$ = $1000 m l$
So, $(1000 - 10) = 990 m l$ water is added to dilute it to decinormal

Suggest Corrections

Similar questions

How much water is needed to dilute 10 ml of 10 N HCl to make it exactly deci-normal?

- {0.2}^{o} C

- {0.5}^{o} C

10 m L

6

0.1 M

0.5 L

6 M

H C l

2 M

10 m l

H C l

Join BYJU'S Learning Program