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Question

How much water should be added to 200 cc of a seminormal solution of NaOH to make it exactly decinormal:

A
1000 cc
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B
400 cc
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C
800 cc
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D
600 cc
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Solution

The correct option is B 800 cc
Given that:
Initial volume of the solution, V1=200cm3

Initial normality of solution, N1=12N

Final normality of solution, N2=110N

Now,
By law of equivalence-

N2V2=N1V1

V2=N1V1N2=12N×200cm3110N

=1000cm3

Volume of water added, V=V2V1

=(1000200)cm3=800cm3

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