How much will the reduction potential of a hydrogen electrode change when its solution initially at $p H = 0$ is neutralized to $p H = 7 ?$

Increase by

0.059 V

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Decrease by

0.059 V

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Increase by

0.41 V

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Decrease by

0.41 V

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Solution

The correct option is D Decrease by $0.41 V$
$(E_{H}^{\oplus} | H_{2})_{1} = - 0.059 p H_{1} = 0$
and
$(E_{H^{\oplus} | H_{2}})_{2} = - 0.059 \times 7 = - 0.41 V$
Hence decrease by $0.41 V$

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