Question

How much will the temperature of $68F$ be in Celsius and Kelvin scale?

• A. ${40}^{\circ }C$ and $313.15K$
• B. ${20}^{\circ }C$ and $293.15K$
• C. ${10}^{\circ }C$ and $283.15K$
• D. ${50}^{\circ }C$ and $323.15K$

Answer 1

The correct option is B ${20}^{\circ }C$ and $293.15K$

Given, temperature in Fahrenheit, $F={68}^{\circ }F$.
Let $C$ be the temperature in Celsius and $K$ be the temperature in Kelvin.
We know, $\frac{F-32}{9}=\frac{C}{5}$ $\Rightarrow \frac{68-32}{9}=\frac{C}{5}$ $\Rightarrow C=5\times \frac{36}{9}={20}^{\circ }C$
Also $K=C+273.15$ $\Rightarrow K=20+273.15=293.15$
Thus, the temperature in Celcius scale $={20}^{\circ }C$ and in Kelvin scale $=293.15K$.