How much work is done by a force 4 N moving an object through a distance 5 m at angle of $60^{o}$ from the direction of force ?

12 J

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20 J

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10 J

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30 J

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Solution

The correct option is C 10 J
Work done is given by:
$W = \to F \cdot \to d = F d cos θ$
$W = 4 \times 5 \times cos 60^{\circ} = 10 J$

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A force of 60 N acts on a body which moves it through a distance of 4 m on a horizontal surface. What is the work done, if the direction of the force is at an angle of $60^{\circ}$ to the horizontal surface?

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How much work is done by a force 4 N moving an object through a distance 5 m at angle of 60o from the direction of force ?

The correct option is C 10 JWork done is given by:W=→F⋅→d=FdcosθW=4×5×cos60∘=10J

How much work is done by a force 4 N moving an object through a distance 5 m at angle of $60^{o}$ from the direction of force ?

The correct option is C 10 J
Work done is given by:
$W = \to F \cdot \to d = F d cos θ$
$W = 4 \times 5 \times cos 60^{\circ} = 10 J$