How much work is done in ergs in pulling a box $2 m$ across a tabletop with a force of $20 N$ in the horizontal direction?

40

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4000

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4 \times 10^{7}

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40 \times 10^{7}

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Solution

The correct option is D $40 \times 10^{7}$
Work done $=$ force $\times$ displacement
or $W = F \times s = 20 \times 2 = 40 J = 40 \times 10^{7} e r g s$

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How much work is done in ergs in pulling a box 2 m across a tabletop with a force of 20 N in the horizontal direction?

The correct option is D 40×107Work done = force × displacementor W=F×s=20×2=40J=40×107ergs

How much work is done in ergs in pulling a box $2 m$ across a tabletop with a force of $20 N$ in the horizontal direction?

The correct option is D $40 \times 10^{7}$
Work done $=$ force $\times$ displacement
or $W = F \times s = 20 \times 2 = 40 J = 40 \times 10^{7} e r g s$