How much work is done in moving a body carrying charge equivalent to that on 5*10power 9 electrons from a point at 25 volts to a point at 40 volts

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Solution

Dear Student ,
The work done is ,
$W = q (V_{2} - V_{1}) = 5 \times 10^{9} \times (40 - 25) = 7 \cdot 5 \times 10^{10} J$

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