How much work is needed to be done on a ball of mass $50 g$ to give it a momentum of $500 g c m s^{- 1}$ ?

10 J

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25 \times 10^{- 5} J

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5 \times 10^{4} J

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0 J

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Solution

The correct option is B $25 \times 10^{- 5} J$
Momentum = $500 g c m / s e c = 500 / (100 \times 1000) = 5 / 1000 K g m / s e c .$
$M a s s = 50 g = 1 / 20 K g$
$K . E = p^{2} / 2 m$ .
$K . E = (5 / 1000)^{2} / (1 / 10)$
$K . E = 25 \times 10^{- 5} J .$
Hence kinetic energy is $25 \times 10^{- 5} J$ .

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