How much work must be done to pull apart the electron and the proton with almost negligible kinetic energies that make up the Hydrogen atom, if the atom is initially in the state with $n = 2$ ?

2.4 eV

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3.4 eV

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1.4 eV

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4.4 eV

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Solution

The correct option is B $3.4 eV$
Work done in pulling electron and proton far away from each other is -

$W = E_{f} - E_{i}$

$W = 0 - E_{i} = 0 - (- \frac{13.6}{n^{2}})$

$\Rightarrow W = \frac{13.6}{2^{2}} = 3.4 eV$

Hence, option $(B)$ is the correct answer.

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How much work must be done to pull apart the electron and the proton with almost negligible kinetic energies that make up the Hydrogen atom, if the atom is initially in the state with n=2?

The correct option is B 3.4 eVWork done in pulling electron and proton far away from each other is - W=Ef−Ei W=0−Ei=0−(−13.6n2) ⇒W=13.622=3.4 eV Hence, option (B) is the correct answer.

How much work must be done to pull apart the electron and the proton with almost negligible kinetic energies that make up the Hydrogen atom, if the atom is initially in the state with $n = 2$ ?

The correct option is B $3.4 eV$
Work done in pulling electron and proton far away from each other is -

$W = E_{f} - E_{i}$

$W = 0 - E_{i} = 0 - (- \frac{13.6}{n^{2}})$

$\Rightarrow W = \frac{13.6}{2^{2}} = 3.4 eV$

Hence, option $(B)$ is the correct answer.