How much work will be done in enlarging the surface area of a soap bubble by $1.0 c m^{2}$ ?

5.0 \times 10^{- 6}

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3.6 \times 10^{- 6}

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7.0 \times 10^{- 6}

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8.0 \times 10^{- 6}

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Solution

The correct option is B $3.6 \times 10^{- 6}$

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Similar questions

2.0 \times 10^{- 3} m

The surface tension of a soap solution is 0.05 Nm^-1. How much work is done to produce a soap bubble of radius 0.03 m?

0.03 N/m

40 {cm}^{2}

10 cm

= 0.03 N/m

1.9 10^{- 2} N / m .

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