How much work would be done by the electric field if Q = 20 C were moved from A (8 V) to B (3.5 V)?
– 90 J
– 80 J
– 70 J
– 60 J
Given:
Q = 20 C
dC = 8 V - 4.5 V = 3.5 V
W = -Q dV
W = - (20 × 3.5)
W = -70 J
Internal energy of a system increases by 60 J when 140 J of heat is added to the gaseous system. The amount of work done would be:
Calculate the work done by electric field when a point charge q is moved from point B to A along the curved path. Given that electric field is created by the stationary charge Q and VA=200V,VB=100V,q=0.05C, length of line segment AB = 10 cm, length of curved path = 20 cm.