How much would a $W k g - w t$ man weigh on the moon in terms of gravitational units?

\frac{W}{6} k g - w t

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Solution

The correct option is D $\frac{W}{6} k g - w t$
The gravity on the moon is approximately 1/6th that of the earth. A man weighing 100 kg-wt on earth would weigh $\frac{100}{6}$ i.e 16.66 kg-wt on the moon. Hence a man with a W kg would weigh $\frac{W}{6}$ kg-wt on the moon.

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is weighed by hanging it to the spring balance, from the ceiling of a car. If the car starts moving around a curve of radius

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at a speed

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. The reading of the spring balance would be

State whether true or false.

In SI system, the gravitational units of work is g wt-m.

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How much would a W kg−wt man weigh on the moon in terms of gravitational units?

The correct option is D W6 kg−wt The gravity on the moon is approximately 1/6th that of the earth. A man weighing 100 kg-wt on earth would weigh 1006 i.e 16.66 kg-wt on the moon. Hence a man with a W kg would weigh W6 kg-wt on the moon.

How much would a $W k g - w t$ man weigh on the moon in terms of gravitational units?

The correct option is D $\frac{W}{6} k g - w t$
The gravity on the moon is approximately 1/6th that of the earth. A man weighing 100 kg-wt on earth would weigh $\frac{100}{6}$ i.e 16.66 kg-wt on the moon. Hence a man with a W kg would weigh $\frac{W}{6}$ kg-wt on the moon.