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Significance of a Molecular Formula

How NaAlO2 fo...

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How NaAlO2 formula formed

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Q. By passing electric current,

N a C l O_{3}

is converted into

N a C l O_{4}

according to the following equation:

N a C l O_{3} + H_{2} O \to N a C l O_{4} + H_{2}

How many moles of

N a C l O_{4}

will be formed when three Faradays of charge is passed through

N a C l O_{3}

?

$C l_{2} + 2 N a O H \to N a C l + A - - + H_{2} O$ to form. A is

(Cold & dilute)

The product(s) when dichlorine hexoxide reacts with $N a O H$ is(are):

$C l_{2} + N a O H \to N a C l + A - - + H_{2} O A$ is

(hot & conc)

N a C l O

solution reacts with

H_{2} S_{4} O

N a C l O

used in the reaction contained 15g of NaClO per litre. The normality of the solution would be:

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Significance of a Molecular Formula

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