How range is 4 times the time in projectile?

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Q. A projectile has a time of flight

T

and range

R

. If the time of flight is double, what happens to the range?

Q. The horizontal range of a projectile is

4 \sqrt{3}

times its maximum height. Its angle of projection will be

A projectile has the same range for two angles of projection. If times of flight in both cases are $t_{1}$ and $t_{2}$ then the range of the projectile is :

Q. The speed of a projectile at its maximum height is

\frac{\sqrt{3}}{2}

times of its initial speed. If range of projectile is

p

times the maximum height reached by it, then find the value of

p

Q. Consider the following statements

A

and

B

and mark the correct option.

A)

The maximum range is

4

times the maximum height attained during its flight in the case of a projectile.

B)

In the case of a projectile the range

R

is related to the time of flight

T

R = 5 T^{2}

. If

g = 10 m s^{- 2}

the angle of projection is

45^{o}

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