How the following conversions can be carried out?
Propene to propan $- 1 -$ ol

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Solution

For the given conversion first ethene is reacted with sulphuric acid where it forms isopropyl hydrogen sulphate as a product.
This product then undergoes hydration reaction where it forms 2-propanaol as a product.
2-propanol is then reacted with conc. $H_{2} S O_{4}$ where it forms propene as a product.
When propene underogoes hydroboration-oxidation reaction in presence of $B_{2} H_{6} + H_{2} O_{2}$ , it forms propan-1-ol as a product.

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How are the following conversions carried out?

(i) Propene → Propan-2-ol

(ii) Benzyl chloride → Benzyl alcohol

(iii) Ethyl magnesium chloride → Propan-1-ol.

(iv) Methyl magnesium bromide → 2-Methylpropan-2-ol.

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