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Question

How to balance a chemical reaction?

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Solution

Let's practice using a reaction from real life, the rusting of iron in the air. To write the reaction, you need to identify the reactants (iron and oxygen) and the products (rust). Next, write the unbalanced chemical equation:

Fe + O2 → Fe2O3

Note the reactants always go on the left side of the arrow. A "plus" sign separates them. Next, there is an arrow indicating the direction of the reaction (reactants become products). The products are always on the right side of the arrow. The order in which you write the reactants and products is not important.

The next step for balancing the chemical equation is to determine how many atoms of each element are present on each side of the arrow:

Fe + O2 → Fe2O3

To do this, keep in mind a subscript indicates the number of atoms. For example, O2 has 2 atoms of oxygen. There are 2 atoms of iron and 3 atoms of oxygen in Fe2O3. There is 1 atom in Fe. When there is no subscript, it means there is 1 atom.

On the reactant side:

1 Fe

2 O

On the product side:

2 Fe

3 O

How do you know the equation isn't already balanced? Because the number of atoms on each side isn't the same. Conservation of mass states mass isn't created or destroyed in a chemical reaction, so you need to add coefficients in front of the chemical formulas to adjust the number of atoms so they will be the same on both sides.

When balancing equations, you never change subscripts. You add coefficients. Coefficients are whole number multipliers. If for example, you write 2 H2O, that means you have 2 times the number of atoms in each water molecule, which would be 4 hydrogen atoms and 2 oxygen atoms. As with subscripts, you don't write the coefficient of "1", so if you don't see a coefficient, it means there is one molecule.

There is a strategy that will help you balance equations more quickly. It is called balancing by inspection. Basically, you look at how many atoms you have on each side of the equation and add coefficients to the molecules to balance out the number of atoms.

  • Balance atoms present in a single molecule of reactant and product first.
  • Balance any oxygen or hydrogen atoms last.

In the example:

Fe + O2 → Fe2O3

Iron is present in one reactant and one product, so balance its atoms first. There is one atom of iron on the left and two on the right, so you might think to put 2 Fe on the left would work. While that would balance iron, you already know you're going to have to adjust oxygen, too, because it isn't balanced. By inspection (i.e., looking at it), you know you have to discard a coefficient of 2 for some higher number.

3 Fe doesn't work on the left because you can't put a coefficient in form of Fe2O3 that would balance it.

4 Fe works, if you then add a coefficient of 2 in front of the rust (iron oxide) molecule, making it 2 Fe2O3. This gives you:

4 Fe + O2 → 2 Fe2O3

Iron is balanced, with 4 atoms of iron on each side of the equation. Next, you need to balance oxygen.

This is the equation balanced for iron:

4 Fe + O2 → 2 Fe2O3

When balancing chemical equations, the last step is to add coefficients to oxygen and hydrogen atoms. The reason is that they usually appear in multiple reactants and products, so if you tackle them first you're usually making extra work for yourself.

Now, look at the equation (use inspection) to see which coefficient will work to balance oxygen. If you put a 2 in form of O2, that will give you 4 atoms of oxygen, but you have 6 atoms of oxygen in the product (coefficient of 2 multiplied by the subscript of 3). So, 2 does not work.

If you try 3 O2, then you have 6 oxygen atoms on the reactant side and also 6 oxygen atoms on the product side. This works! The balanced chemical equation is:

4 Fe + 3 O2 → 2 Fe2O3

Note: You could have written a balanced equation using multiples of the coefficients. For example, if you double all of the coefficients, you still have a balanced equation:

8 Fe + 6 O2 → 4 Fe2O3


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