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Question

How to calculate sin37

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Solution

We know that 37<90

Hence 37 is acute.

From ABC,C is acute.

B=90

A+B+C=180

C=180(A+B)

C=180(37+90)

C=180127=53

Let AB=3 units,BC=4 units then

By Pythagoras theorem,AC2=AB2+BC2

AC2=32+42=9+16=25

AC=5 units

sin37=ABAC=35

1452824_862880_ans_0a32cf62826d4a33a3f0f121a8c397d4.PNG

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