How to calculate the number of generations of binary fissions required for the production of 256 bacteria from 8 bacteria?

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Solution

Number of generations = n
Initially, Number of bacteria = 8
Final number of bacteria = 256
Formula for one bacteria to grow = $2^{n}$
For 8 number of bacteria
$8 \times 2^{n} = 256$
$2^{n} = \frac{256}{8}$
$2^{n} = 32$
$n = 5$

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How to calculate the number of generations of binary fissions required for the production of 256 bacteria from 8 bacteria?

Number of generations = n Initially, Number of bacteria = 8 Final number of bacteria = 256 Formula for one bacteria to grow = 2n For 8 number of bacteria 8×2n=256 2n=2568 2n=32 n=5

Number of generations = n
Initially, Number of bacteria = 8
Final number of bacteria = 256
Formula for one bacteria to grow = $2^{n}$
For 8 number of bacteria
$8 \times 2^{n} = 256$
$2^{n} = \frac{256}{8}$
$2^{n} = 32$
$n = 5$