Question

How to calculate the value of $g$ at the surface of the Moon? $(M=7.35x{10}^{22}kg,R=1738km)$

Answer 1

Step 1: Given data

Mass of moon $M=7.35x{10}^{22}kg$

Radius of moon $R=1738km=1738\times {10}^{3}m$

We know that the value of gravitation constant,

$G=6.67\times {10}^{-11}Nm²/kg²$

Step 2: Calculate acceleration due to gravity of the Moon

We know that the acceleration due to gravity can be given as,

$g=\frac{GM}{R^2}$

Upon substituting the values we get,

$g=\frac{6.67\times {10}^{-11}\times 7.35\times {10}^{22}}{{\left(1738\times {10}^3\right)}^2}$

$=1.623m/s^2$

Hence, the value of $g$ on moon is $1.623m/s^2$.