How to find a oxidation number of the Coordinate compound?
How to find a oxidation number of the Coordinate compound?
The most general solution: you should substract the overall charge of the ligands from the overall charge of the coordinate compound.
For example, potassium hexacyanoferrate (III): K3[Fe(CN)6]K3[Fe(CN)6]. The coordinate compound here is [[Fe(CN)6]3−Fe(CN)6]3−. There are 6 CN ligands, each of them with the charge -1. The overall charge is 3-. Therefore, the charge of the central atom, which is equal to the oxidation state, is :
−3−6∗(−1)=−3+6=+3−3−6∗(−1)=−3+6=+3
Another example is [Ag(NH3)4]OH.[Ag(NH3)4]OH. Here the coordinate compound is [Ag(NH3)4]+[Ag(NH3)4]+. Ligands are just ammonium molecules which are neutral - the charge of each ligand is zero. Therefore, the charge of the central metal is equal to the charge of the complex, and the oxidation state is +1
The most general solution: you should substract the overall charge of the ligands from the overall charge of the coordinate compound.
For example, potassium hexacyanoferrate (III): K3[Fe(CN)6]K3[Fe(CN)6]. The coordinate compound here is [[Fe(CN)6]3−Fe(CN)6]3−. There are 6 CN ligands, each of them with the charge -1. The overall charge is 3-. Therefore, the charge of the central atom, which is equal to the oxidation state, is :
−3−6∗(−1)=−3+6=+3−3−6∗(−1)=−3+6=+3
Another example is [Ag(NH3)4]OH.[Ag(NH3)4]OH. Here the coordinate compound is [Ag(NH3)4]+[Ag(NH3)4]+. Ligands are just ammonium molecules which are neutral - the charge of each ligand is zero. Therefore, the charge of the central metal is equal to the charge of the complex, and the oxidation state is +1
