Question

How to find area of triangle?

Answer 1

Area of $\Delta =\frac{1}{2}\times b\times h$ [b is base and h is height of perpendicular to base from opposite vector]
$=\sqrt{s(s-a)(s-b)(s-c)}$
Where S is semi perimeter of $\Delta s=\frac{a+b+c}{2}$ [a,b,c are length of side of $\Delta$]