how to find oxidation number of "Ba" in "BaO2" and "Si" in "SiO2"..... What would be its answer???

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Solution

If the oxidation number of the oxygen in BaO2 were -2, the oxidation number of the barium would have to be+4. But elements in Group IIA can't form +4 ions. This compound must be barium peroxide, [Ba2+][O22-]. Barium therefore is +2 and oxygen is -1.
The oxidation number of oxygen is -1 because the compound is a peroxide.

But this is not in the case of SiO2
1 O oxidation number is = -2
2 O oxidation number is = -4
so oxidation number of O is = -4

Oxidation number of si is = +4

because oxidation number on any compound should be zero if oxidation number of oxygen is -4 then oxidation number of si must be +4
Hope you understand the difference between the two compounds

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