How to find the area of a triangle if the figure is octagon and pentagon

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Solution

$A r e a o f o c t a g o n = 2 (1 + \sqrt{2}) a^{2} w h e r e a i s s i d e . a n d a r e a o f p e n t a g o n = \frac{1}{4} \sqrt{5 (5 + 2 \sqrt{5})} a^{2} w h e r e a i s s i d e l e n g t h .$

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How to find the area of a triangle if the figure is octagon and pentagon

Area of octagon = 21+2a2where a is side. and area of pentagon = 1455+25a2where a is side length.

$A r e a o f o c t a g o n = 2 (1 + \sqrt{2}) a^{2} w h e r e a i s s i d e . a n d a r e a o f p e n t a g o n = \frac{1}{4} \sqrt{5 (5 + 2 \sqrt{5})} a^{2} w h e r e a i s s i d e l e n g t h .$