How to find the point $E$ & point $F$ in this diagram, if
ED=2x+8y=28 and OF=2x+2y=17.

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Solution

REF.Image.
$E D = 2 x + 8 y = 28$
$F o r x = 0, y = \frac{7}{2}, (0, \frac{7}{2})$
$F o r y = 0, x = 14, (14, 0)$
$△ O F = 2 x + 2 y = 17$
$F o r x = 0, y = 17 / 2$ & $F o r y = 0, x = \frac{17}{2}$
hence $(0, \frac{17}{2})$ & $(\frac{17}{2}, 0)$
Intersection of line gives, $y = 11 / 6 .2 x = \frac{20}{3}$

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