How to find the total resistance of an electric circuit if there is resistance R1 ,R2, R3, R4, R5 individualaly.

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Solution

Case:1) total resistance in series circuit

For any number of individual resistors connected in series,the total resistance is the sum of each of the individual values.
Rt=R1+R2+R3+R4+R5

Case:2) Total resistance in parallel circuit

Since Vs is the voltage across each of the parallel resistors in above figure,by Ohm’s law I=Vs/R:

Vs/Rt= Vs/R1+ Vs/R2+ Vs/R3+Vs/R4+Vs/R5

The term Vs can be factored out of the right side of the equation and canceled with Vs on the left side,leaving only the resistance terms.

1/Rt = 1/R1 + 1/R2 + 1/R3+1/R4+1/R5

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Similar questions

R_{1} = 10 Ω

R_{2} = 40 Ω

R_{3} = 30 Ω

R_{4} = 20 Ω

R_{5} = 60 Ω

r_{1}, r_{2}, r_{3}

r_{4}

r_{1} = r_{2} = r_{3} = r_{4} = 2.0 Ω

In the circuit given E = 6.0 V, $R_{1} = 100 Ω, R_{2} = R_{3} = 50 Ω, R_{4} = 75 Ω$ . The equivalent resistance of the circuit, in $Ω$ , is

R_{3}

(R_{1} = 15 Ω, R_{2} = 15 Ω, R_{3} = 30 Ω, R_{4} = 35 Ω)

R_{1}, R_{2}, R_{3}, R_{4}

R_{5}

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