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Paraxial Approximation

How to identi...

Question

How to identify the centre of curvature, focus, principal axis of the concave mirror ?

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Solution

$W h e n l i g h t r a y s c o m e f r o m i n f i n i t y, p o i n t a t w h i c h t h e y p r o d u c e i m a g e a f t e r r e f l e c t i n g f r o m t h e m i r r o r, i s c a l l e d t h e f o c u s . W H e n s o u r c e o f l i g h t i s k e p t o n t h e f o c u s o f t h e m i r r o r, l i g h t r a y s b e c o m e p a r a l l e l t o t h e a x i s w h i c h i s k n o w t h e p r i n c i p l e a x i s . T h e p o i n t a t w h i c h p r i n c i p l e a x i s i n t e r s e c t t h e m i r r o r, i s c a l l e d p o l e o f t h e m i r r o r .$

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Similar questions

Q. Where will the image form when we place an object, on the principal axis of a concave mirror at a point between focus and centre of curvature?

Q. Question 2
The image formed by a concave mirror is observed to be virtual, erect and larger than the object. Where should be the position of the object?

(a) Between the principal focus and the centre of curvature
(b) At the centre of curvature
(c) Beyond the centre of curvature
(d) Between the pole of the mirror and its principal focus

Q. A ray of light is incident on a concave mirror. It is parallel to the principal axis and its height from principal axis is equal to the focal length of the mirror. The ratio is the distance of point B to the distance of the focus from the centre of curvature is :

(AB is the reflected ray).

Q. A light ray falling parallel to the principal axis of a concave mirror passes through the centre of curvature after reflection.

Q. The image of a real object, placed perpendicular to the principal axis of a concave mirror, will be virtual and erect if the position of object is
(a) At centre of curvature C
(b) Between F and centre of curvature C
(c) Between pole P and focus F
Choose the correct option among the following.

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